((x+1)/(x+2))+((x+3)/(x+4))=(x+15)/(x^2+6x+8)

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Solution for ((x+1)/(x+2))+((x+3)/(x+4))=(x+15)/(x^2+6x+8) equation: 



((x+1)/(x+2))+((x+3)/(x+4))=(x+15)/(x^2+6x+8)

We move all terms to the left:

((x+1)/(x+2))+((x+3)/(x+4))-((x+15)/(x^2+6x+8))=0



Domain of the equation: (x+2))!=0

x∈R





Domain of the equation: (x+4))!=0

x∈R





Domain of the equation: (x^2+6x+8))!=0

x∈R



We calculate fractions


((6x+(x+1)*(x+4))*x^2)/((x+2))*(x+4))*(x^2+6x+8)))+((6x+(x+3)*(x+2))*x^2)/((x+2))*(x+4))*(x^2+6x+8)))+(-((x+15)*(x+2))*x)/((x+2))*(x+4))*(x^2+6x+8)))=0

We can not solve this equation

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